1. (b) 10 miles each. Pythagoras Theorem. 2. Each Cow has 2 eyes and 4 legs and each bird has 2 eyes and 2 legs. Lets call each eye as x and each leg as y. Also each bird is n and each cow is m so: n(2x+2y) + m(2x + 4y) = 172x + 344y 2x (n+m) + 2y(n+2m) = 172x + 344y (n+m) = 86 and (n+2m) = 172 n = 86 - m 86 - m + 2m = 172 or m = 86 This implies n = 0. The owner has 0 birds and 86 cows. 3. This is a classic probability puzzle and many puzzles are based on this logic. If the person picks up two socks then there is a possibility of them being different in colour. If he picks up three socks then they are guaranteed red or white. So the minimum number of socks required are three (3). 4. Let the number be x 105 - x = y x = 105 - y 13x = 105 + y 14 x = 210 x = 15 5. 10 minutes. The total time was one hour and already 50 minutes are over. 6. You can assume that when the fly lands on cyclist 1 they are 50 miles apart. The fly has to travel 50 + x miles at 16 miles/hour. Here x is the additional distance at 10 miles/hour. So the problem is now simplified as y = 50 + x (distance) (50 + x)/16 = x/10 (time) 500 + 10x = 16x 6x = 500 x = 250/3 = 83.33 y = 133.33 7. (c) daughter Back to Questions Back to Puzzles Home |

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